4sin^2(2t)+4cos^2(2t)=

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Solution for 4sin^2(2t)+4cos^2(2t)= equation:


Simplifying
4sin2(2t) + 4cos2(2t) = 0

Remove parenthesis around (2t)
4in2s * 2t + 4cos2(2t) = 0

Reorder the terms for easier multiplication:
4 * 2in2s * t + 4cos2(2t) = 0

Multiply 4 * 2
8in2s * t + 4cos2(2t) = 0

Multiply in2s * t
8in2st + 4cos2(2t) = 0

Remove parenthesis around (2t)
8in2st + 4cos2 * 2t = 0

Reorder the terms for easier multiplication:
8in2st + 4 * 2cos2 * t = 0

Multiply 4 * 2
8in2st + 8cos2 * t = 0

Multiply cos2 * t
8in2st + 8cos2t = 0

Reorder the terms:
8cos2t + 8in2st = 0

Solving
8cos2t + 8in2st = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-8in2st' to each side of the equation.
8cos2t + 8in2st + -8in2st = 0 + -8in2st

Combine like terms: 8in2st + -8in2st = 0
8cos2t + 0 = 0 + -8in2st
8cos2t = 0 + -8in2st
Remove the zero:
8cos2t = -8in2st

Divide each side by '8os2t'.
c = -1in2o-1s-1

Simplifying
c = -1in2o-1s-1

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